Question

Cards are drawn from a pack of 52 cards one by one. The probability that exactly 10 cards will be drawn before the first ace cards is

• A. $\frac{241}{1456}$
• B. $\frac{164}{4165}$
• C. $\frac{451}{884}$
• D. $\frac{451}{1465}$

Answer 1

The correct option is B $\frac{164}{4165}$

P{(first ten draws non-ace) (${11}^{th}$ ace)} = $\frac{48C^{10}}{52C^{10}}\times \frac{4}{42}=\frac{164}{4165}.$