CArds bearing numbers 1, 3, 5,..., 35 are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card bearing (iI) a prime number less than 15, (ii) a number divisible by 3 and 5.

Open in App

Solution

(i). Event: less than 15

Sample space - 1,3, 5, 7, 9, 11, 13, 15, 17, 19, 21, 23, 25, 27, 29, 31, 33, 35.

Total no. of outcomes = 18

No of favourable outcome=5 (i.e - 3, 5, 7, 11, 13. )

Therefore

$P (E) = \frac{5}{18}$

(ii). Since both 15 and 30 are divisible by 3 as well as 5 but since 30 is not included in sample space. Therefore,

Favourable outcome = 1 (ie. 15)

$P (E) = \frac{1}{18}$

Suggest Corrections

142

Similar questions

Q. Cards bearing numbers

2, 4, 6, 8, 10, 12, 14, 16, 18

and

20

are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card which is
(i) a prime number
(ii) A number is divisible by 4.

Q. Cards bearing numbers 2, 3, 4,......,11 are kept in a bag. A card is drawn at random from the bag Find the probability of getting a card with a prime number.

Q. Cards bearing numbers

2, 4, 6, 8, 10, 12, 14, 16, 18

and

20

are kept in a bag. A card is drawn at random from the bag. Find the probability of getting a card which is?

(A) A prime number.

(B) A number is divisible by

4

6

(D) An odd number.

Q. Cards bearing numbers 2, 3, 4, ..., 11 are kept in a bag. A card is drawn at random from the bag. The probability of getting a card with a prime number is [CBSE 2012]

(a)

\frac{1}{2}

(b)

\frac{2}{5}

(c)

\frac{3}{10}

(d)

\frac{5}{9}

Cards marked with numbers 1,3,5,..., 101 are placed in a bag and mixed thoroughly. A card is drawn at random from the bag. Find the probability that the number on the drawn card is (i) less than 19, (ii) a prime number less than 20.

Join BYJU'S Learning Program