Cards bearing numbers 3 to 20 are placed in a bag and mixed thoroughly. A card is taken out randomly from the bag. What is the probability that the number on the card is an even number?

$1$

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$\frac{4}{5}$

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$\frac{2}{3}$

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$\frac{1}{2}$

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Solution

The correct option is D
$\frac{1}{2}$

Even numbers from 3 to 20 are 4, 6, 8, 10, 12, 14, 16, 18, 20 = 9 numbers.
Total numbers of card = 18
Therefore the probability that the number on the card taken out is an even number = $\frac{9}{18} = \frac{1}{2}$

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Cards bearing numbers 3 to 20 are placed in a bag and mixed thoroughly. A card is taken out randomly from the bag. What is the probability that the number on the card is an even number?

The correct option is D 12 Even numbers from 3 to 20 are 4, 6, 8, 10, 12, 14, 16, 18, 20 = 9 numbers. Total numbers of card = 18 Therefore the probability that the number on the card taken out is an even number =918=12

The correct option is D
$\frac{1}{2}$

Even numbers from 3 to 20 are 4, 6, 8, 10, 12, 14, 16, 18, 20 = 9 numbers.
Total numbers of card = 18
Therefore the probability that the number on the card taken out is an even number = $\frac{9}{18} = \frac{1}{2}$