Question

Carl walked 4m west and 5m south. How far he is from his starting point?

• A. $\sqrt{43}meters$
• B. $\sqrt{47}meters$
• C. $\sqrt{41}meters$
• D. $\sqrt{37}meters$

Answer 1

The correct option is C $\sqrt{41}meters$


According to the question carl walks 4m west and 5m south. So the net displacement is AB.
$A{B}^2=(4{)}^2+(5{)}^2$
$=\left(16\right)+\left(25\right)$
$=41$
$\therefore AB=\sqrt{41}meters$.