Question

carla is 5 years old and jim is 13 years younger than peter . one year ago , peter's age was twice the sum of carla's &Jim's age . find the present age of each one of them

Answer 1

$$\begin{gathered} \mathrm{Age}\mathrm{of}\mathrm{Carla}=5\mathrm{yrs} \\ \mathrm{Let}\mathrm{age}\mathrm{of}\mathrm{Peter}=\mathrm{x}\mathrm{yrs} \\ \mathrm{Age}\mathrm{of}\mathrm{Jim}=\left(\mathrm{x}-13\right)\mathrm{yrs} \\ \mathrm{ONE}\mathrm{YEAR}\mathrm{AGO}, \\ \mathrm{Peter}\text{'}\mathrm{s}\mathrm{age}=\left(\mathrm{x}-1\right)\mathrm{yrs} \\ \mathrm{Carla}\text{'}\mathrm{s}\mathrm{age}=5-1=4\mathrm{yrs} \\ \mathrm{Jim}\text{'}\mathrm{s}\mathrm{age}=\left(\mathrm{x}-14\right)\mathrm{yrs} \\ \mathrm{x}-1=2\left[\left(5-1\right)+\left(\mathrm{x}-13-1\right)\right] \\ \mathrm{x}-1=2\left[4+\left(\mathrm{x}-14\right)\right] \\ \mathrm{x}-1=2\left[\mathrm{x}-10\right] \\ \mathrm{x}-1=2\mathrm{x}-20 \\ \mathrm{x}=19 \\ \mathrm{Age}\mathrm{of}\mathrm{Peter}=19\mathrm{yrs} \\ \mathrm{Age}\mathrm{of}\mathrm{Jim}=19-13=6\mathrm{yrs} \end{gathered}$$