Question

Carnot cycle works with isentropic compression ratio of $5$ bar and isothermal ratio of $2$. The volume of air at beginning of the isothermal expansion is $0.3m^3$. If the temperature and pressure is limited to $550$K and $21$ bar, Determine Minimum temperature in the cycle.

Answer 1

$\eta =-\frac{1}{{\gamma }^{\gamma -1}}=1-\frac{1}{5^{2-1}}=1-\frac{1}{5}=\frac{4}{5}=80$

Also, $\eta =1-\frac{T_2}{T_1}\Rightarrow 1-\frac{T_2}{550}=\frac{550-T_2}{550}\Rightarrow \frac{4}{5}=\frac{550-T_2}{550}\Rightarrow 550-T_2=440\therefore T_2=110K$