Carnot engine operating between temperature T1and T2 are efficiency 16-When T2 is lowered by 62 K its efficiency increases to 13 -Then T1and T2 are - respectively

The correct option is A 372 K and 310 KEfficiency of Carnot engine is given by #10; #10; η_1=1 T_2T_1 #10; #10; #10; 16=1 T_2T_1 #10; #1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Second Law of Thermodynamics

Carnot engine...

Question

Carnot engine operating between temperature $T_{1} a n d T_{2}$ are efficiency $\frac{1}{6}$ .When $T_{2}$ is lowered by 62 K its efficiency increases to $\frac{1}{3}$ .Then $T_{1} a n d T_{2}$ are , respectively

372 K and 310 K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

372 K and 330 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

330 K and 268 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

310 K and 248 K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 372 K and 310 K
Efficiency of Carnot engine is given by

$η_{1} = 1 - \frac{T_{2}}{T_{1}}$

$\frac{1}{6} = 1 - \frac{T_{2}}{T_{1}}$

$\frac{T_{2}}{T_{1}} = \frac{5}{6} . . . . . . . . . (1)$

When T₂ is lowered by 62K its efficiency increases to 1/3

So,

$η_{2} = 1 - \frac{T_{2} - 62}{T_{1}}$

$\frac{1}{3} = 1 - \frac{T_{2} - 62}{T_{1}}$

$2 T_{1} - 3 T_{2} + 186............ (2)$

Solving equation (1) and (2)

$T_{1} = 372 K$

$T_{2} = 310 K$

Suggest Corrections

Similar questions

Q. A carnot engine operating between temperature

T_{1}

and

T_{2}

has the efficiency of

\frac{1}{6}

. When the temperature

T_{2}

is lowered by 62K, it efficiency becomes

\frac{1}{3}

, Then temperature

T_{1}

and

T_{2}

respectively are

Q. A Carnot engine operating between temperatures

T_{1}

and

T_{2}

has efficiency

\frac{1}{6}

. When

T_{2}

is lowered by

62

K

, it's efficiency increases to

\frac{1}{3}

. Then

T_{1}

and

T_{2}

are, respectively :

Q. A Carnot engine operating between temperatures

T_{1}

and

T_{2}

has efficiency 0.2. When

T_{2}

is reduced by 60 K, its efficiency increases to 0.4. Then,

T_{1}

and

T_{2}

are respectively

Q. A Carnot engine operating between temperatures

T_{1}

and

T_{2}

has efficiency

\frac{1}{6}

. When

T_{2}

is lowered by

62 K

, its efficiency increases to

\frac{1}{3}

. Then

T_{1}

and

T_{2}

are, respectively :

Q. A carnot engine operating between temperature

T_{1}

and

T_{2}

has the efficiency of

\frac{1}{6}

. When the temperature

T_{2}

is lowered by 62K, it efficiency becomes

\frac{1}{3}

, Then temperature

T_{1}

and

T_{2}

respectively are

Join BYJU'S Learning Program

Carnot engine operating between temperature T1andT2 are efficiency 16.WhenT2 is lowered by 62 K its efficiency increases to 13 .Then T1andT2 are , respectively

The correct option is A 372 K and 310 KEfficiency of Carnot engine is given by η1=1−T2T1 16=1−T2T1 T2T1=56.........(1) When T2 is lowered by 62K its efficiency increases to 1/3 So, η2=1−T2−62T1 13=1−T2−62T1 2T1−3T2+186............(2) Solving equation (1) and (2) T1=372K T2=310K

Carnot engine operating between temperature $T_{1} a n d T_{2}$ are efficiency $\frac{1}{6}$ .When $T_{2}$ is lowered by 62 K its efficiency increases to $\frac{1}{3}$ .Then $T_{1} a n d T_{2}$ are , respectively