Question

Carry out the division $-36y^3÷9y^2$

• A. $y^2$
• B. $-2y$
• C. $3y^2$
• D. $-4y$

Answer 1

The correct option is D $-4y$

$-36y^3÷9y^2$
$-36y^3=-2\times 2\times 3\times 3\times y\times y\times y$
$9y^2=3\times 3\times y\times y$
$-36y^3÷9y^2=\frac{-2\times 2\times 3\times 3\times y\times y\times y}{3\times 3\times y\times y}$
$=-4y$