Question

Carry out the following divisions
$72a^3{b}^4{c}^5$ by $8a{b}^2{c}^3$

• A. $9a^2{b}^2{c}^2$
• B. $8a^2{b}^2{c}^2$
• C. $9a^3{b}^2{c}^2$
• D. $9a^2{b}^{2}c$

Answer 1

Answer: (A)

$9a^2{b}^2{c}^2$

$\frac{72a^3{b}^4{c}^5}{8a{b}^2{c}^3}$

$=\frac{72}{8}\times \frac{a^3}{a^1}\times \frac{b^4}{h^2}\times \frac{c^5}{c^3}$

$=9\times a^{3-1}\times b^{4-2}\times c^{5-3}$

$=9a^2{b}^2{c}^2$