Question

Carry- over factor $C_{AB}$ for the beam as shown in the figure below is

• A. $\frac{1}{2}$
• B. $\frac{1}{3}$
• C. $1$
• D. $\frac{1}{4}$

Answer 1

The correct option is A $\frac{1}{2}$



$R_A\times \left(\frac{2L}{3}\right)=M$

$\Rightarrow R_A=\left(\frac{3M}{2L}\right)$

$M_B=\left(\frac{3M}{2L}\right)\times \left(\frac{L}{3}\right)$

$M_B=\left(\frac{M}{2}\right)$

$\text{Carry over factors,}{C}_{AB}=\frac{M_B}{M_A}=\frac{M/2}{M}=\left(\frac{1}{2}\right)$

$\Rightarrow C_B=\frac{1}{2}$