wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

(CaSO4) with Ksp=4.9×105 is found to have 4×107 M in Ca2+ and 2.5×108 M in SO24.
The equilibrium state of this solution with respect to (CaSO4) is :

A
Unsaturated solution
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Saturated solution
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Supersaturated solution
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Cannot be determined
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A Unsaturated solution
The equilibrium established will be:
CaSO4 (s)Ca2+ (aq.)+SO24 (aq.)

Finding the ion product Qsp
Qsp=(4×107)×(2.5×108)Qsp=1014<Ksp=4.9×105

Since, QspKsp<1
The solution is unsaturated in CaSO4.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon