Question

Catalyst used industrially which speeds up the conversion of $S{O}_2$ to $S{O}_3$ in the production of $H_{2}SO4$ in the laboratory or industrially. Write the equation for the conversion of $S{O}_2$ to $S{O}_3$. Why does this reaction supply energy. What is the name of the compound formed between $S{O}_3$ and $H_{2}S{O}_4$

• A. Vanadium pentaoxide
• B. Nickel
• C. Cobalt
• D. Iron

Answer 1

The correct option is A Vanadium pentaoxide

One catalyst used industrially which speeds up the conversion of sulphur dioxide to sulphur trioxide is Vanadium pentaoxide or platinised asbestos.
${2SO}_2+O_2\underset{V_2{O}_5}{\overset{450C}{\to }}{2SO}_3$
The reaction supplies energy as the reaction is exothermic in nature.
The name of the compound formed between $S{O}_3$ and $H_{2}S{O}_4$ is Oleum or Pyrosulphuric acid.