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Question

Catalytic decomposition of nitrous oxide by gold at 9000C at an initial pressure of 200 mm was 50 % in 53 min and 73 % in 100 min. The amount that will compose in 100 min at the same temperature but at an initial pressure of 600 mm is (multiply the answer by 100) :

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Solution

We have, K=(2.303t)log10[a(ax)] --- (1)
Case I : t1/2=53 minutes
K1=(2.30353)log10[200(200100)]=1.307×102 minute1

Case II : t73=100 minutes
K2=(2.303100)log10[200(200146)]=1.309×102minute1

Since the value of K is constant. Hence it is first order reaction, the time required to complete any fraction is independent of its initial concentration of reactant.

73% of N2O will decomposes when the initial concentration is 600 mm which corresponds to a pressure of
600 mm100=4.38mm


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