Cathode- 2H 2 O- 2e - - H 2 -2 OH -Anode- xOH - - O 2 - 2H 2 O- ye -Overall- 2H 2 O- 2H 2 - O 2Find the value of x and y-

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Standard X

Chemistry

Electrolysis of Aqueous Sodium Chloride

Cathode: 2H...

Question

Cathode: ${2 H}_{2} O + {2 e}^{-} \to H_{2} + 2 {O H}^{-}$
Anode: ${x O H}^{-} \to O_{2} + {2 H}_{2} O + {y e}^{-}$
Overall: ${2 H}_{2} O \to 2 H_{2} + O_{2}$
Find the value of x and y:

x = 2, y = 2

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x = 2, y = 4

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x = 4, y = 4

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x = 4, y = 2

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Solution

The correct option is C $x = 4, y = 4$
Electrolysis of water is the decomposition of water into oxygen and hydrogen due to passage of electric current. In electrolysis water splits into its atomic components hydrogen and oxygen using electricity.
$C a t h o d e : {2 H}_{2} O + {2 e}^{-} \to H_{2} + 2 {O H}^{-} A n o d e : {4 O H}^{-} \to O_{2} + {2 H}_{2} O + {4 e}^{-} O v e r a l l : {2 H}_{2} O \to 2 H_{2} + O_{2}$

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Q. Find the value of

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In a fuel cell, hydrogen and oxygen react to produce electricity. In the process, hydrogen gas is oxidized at anode and oxygen at cathode. If 67.2 L of $H_{2}$ at STP reacts in 15 min, the average current (in A) produced is :

Anode reaction : $H_{2} + 2 ⊖ O H \to 2 H_{2} O + 2 e^{-}$

Cathode reaction :

O_{2} + 2 H_{2} O + 2 e^{-} \to 4 ⊖ O H

(write your answer to nearest integer)

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Cathode: 2H2O+2e−→H2+2OH−Anode: xOH−→O2+2H2O+ye−Overall: 2H2O→2H2+O2Find the value of x and y:

Cathode: ${2 H}_{2} O + {2 e}^{-} \to H_{2} + 2 {O H}^{-}$
Anode: ${x O H}^{-} \to O_{2} + {2 H}_{2} O + {y e}^{-}$
Overall: ${2 H}_{2} O \to 2 H_{2} + O_{2}$
Find the value of x and y: