Cathode ray particles have a mass of ________ times that of hydrogen nucleus.

1

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\frac{1}{10}

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1840

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\frac{1}{1840}

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Solution

The correct option is D $\frac{1}{1840}$
Since cathode ray particle are negatively charged i.e. made of electron.

Mass of 1 electron = $9.1 \times 10^{- 31} k g$

Whereas hydrogen nucleus consists of 1 proton.

Mass of proton = $1.67 \times 10^{- 27} k g$

On comparing both the masses,

$\frac{mass of electron}{mass of proton} = \frac{mass of cathode ray article}{mass of hydrogen nucleus}$

$= \frac{9.1 \times 10^{- 31}}{1.67 \times 10^{- 27}}$

$= \frac{1}{1833} \frac{1}{1840}$

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