Question

Cations absorb $6.023\times {10}^{22}$ electrons for their reduction. How many equivalents of the ion are reduced?

• A. $0.1$
• B. $0.01$
• C. $0.001$
• D. $0.0001$

Answer 1

The correct option is A $0.1$

1 equivalent of ion absorbs 6. 023 $\times {10}^{23}$ electrons

No. of equivalents reduced = $\frac{6.023\times {10}^{22}}{6.023\times {10}^{23}}$= 0.1