wiz-icon
MyQuestionIcon
MyQuestionIcon
4
You visited us 4 times! Enjoying our articles? Unlock Full Access!
Question

Cell A has osmotic potential of –18 bars and pressure potential of 8 bars, whereas cell B has osmotic potential of –14 bars and pressure potential 2 bars. The direction of flow of water will be

A
from cell B to cell A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
from cell A to cell B
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
no flow of water
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
in both the directions
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B from cell A to cell B
Cell A:
Osmotic potential = -18 bars
Osmotic Pressure (OP) = 18 bars
Pressure potential = 8 bars
Turgor Pressure (TP) = 8 bars

Therefore, DPD (diffusion pressure deficit) = OP - TP = 18 - 8 = 10 bars.

Cell B:
Osmotic potential = -14 bars
Osmotic Pressure (OP) = 14 bars
Turgor Pressure (TP) = 2 bars

Therefore, DPD = OP - TP = 14 - 2 = 12 bars.

Hence, water will move from lower DPD to higher DPD, i.e., from A to B.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon