cell supplies a current of 0.9 A through a 2 ohm resistor and current of 0.3 A through a 7 ohm resistor. What is the internal resistance of the cell?
If E the emf of the cell and r its internal resistance then
E2+r=0.9 and
E7+r=0.3
dividing the two equations we get
7+r2+r=93
r=0.5 ohm