The correct option is B (−5−2√3,5+2√3),(−5+2√3,5−2√3)
It is clear that circle in II quadrant
∴ Centre is (−h,h),
then radius=√(−2+h)2+(3−h)2=|h|
On simplifying, we get
⇒2h2−10h+4+9=h2
⇒h2−10h+13=0
∴h=10±√100−522=5±2√3
Centres are (−(5±2√3),5±2√3)
i.e., (−5−2√3,5+2√3) and (−5+2√3,5−2√3)