Centre of the circle $(x - 3)^{2} + (y - 4)^{2}$ = 5 is

(3, 4)

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(-3, -4)

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(4, 3)

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(-4, -3)

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Solution

The correct option is A (3, 4)
We can see that the given equation is given in the form of $(x - a)^{2} + (y - b)^{2} = (r)^{2}$
So, the center of the circle will be (3,4)

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4 \sqrt{5}

(x - 3)^{2} + (y - 4)^{2} = 8^{2} .

(x - 3)^{2} + (y - 4)^{2} = 8^{2}

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