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Question

Centre of the ellipse 4(x2y+1)2+9(2x+y+2)2 = 5 is


  1. (-2,2) 

  2. (1,5)

  3. (-5,2)

  4. (-1,0)


Solution

The correct option is D

(-1,0)


4(x2y+1)2+9(2x+y+2)2 = 5

x - 2y + 1 = 0

2x + y + 2 = 0

x5 = y0 = 15

x = -1, y = 0

Center = (-1,0)

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