Centripetal acceleration of a cyclist completing 7 rounds in a minute along a circular track of radius $5 m$ with a constant speed, is

2.7 m / s^{2}

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4 m / s^{2}

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3.78 m / s^{2}

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6 m / s^{2}

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Solution

The correct option is A $2.7 m / s^{2}$
Centripetal acceleration $= V ² / r$
$V =$ Distance / time.
$7$ revolutions per minute.
$1$ revolution $= 2 \times 3.142 \times 5 = 31.42 m$
$7$ revolutions $= 7 \times 22 / 7 \times 2 \times 5 = 220 m$
$220$ m in $60$ second
In one second we have :
$= 3.667 m / s$
Centripetal acceleration $= {3.667}^{2} / 5 = 2.689 m / s^{2}$
Hence, Option $A$ is correct .

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Centripetal acceleration of a cyclist completing 7 rounds in a minute along a circular track of radius 5m with a constant speed, is

The correct option is A 2.7m/s2Centripetal acceleration =V²/rV= Distance / time.7 revolutions per minute.1 revolution =2×3.142×5=31.42m7 revolutions =7×22/7×2×5=220m220 m in 60 secondIn one second we have :=3.667m/sCentripetal acceleration=3.6672/5=2.689m/s2Hence, Option A is correct .

Centripetal acceleration of a cyclist completing 7 rounds in a minute along a circular track of radius $5 m$ with a constant speed, is