Question

Cerium (Z=58) shows +4 oxidation state because:

• A. In +4 state the configuration is $6s^{0}5d^{0}4f^0$
• B. In +4 state the configuration is $6s^{2}6p^{6}5d^{10}$
• C. +5 state is unstable
• D. +3 state is more stable than + 4 state

Answer 1

The correct option is A In +4 state the configuration is $6s^{0}5d^{0}4f^0$

Cerium (Z=58) shows +4 oxidation state also because,in +4 state the configuration is $6s^{0}5d^{0}4f^0$ and it is stable because of $4f^0$ configuration.