certain amount of heat is given to
100g of copper to increase its temperature by 21 deg c. if the same amount of heat is given to 50 g of water, then the rise in its temperature is (specific heat of copper = 400 j kg^-1 k ^-1and that for water is 4200 j kg^-1 k^-1)

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Solution

Dear Student

Heat energy in the copper system is $Q = m s ∆ T$
Where m is mass of copper m= 100 g =0.1 kg
s is the specific heat s= 400 J kg^-1k^-1
T is the temperature T= 21 C⁰=273+21=294 K
Q=0.1 x 400 x 294 =11760 J

Equal amount of heat is given to the water

$Q = m s ∆ T$
11760=0.054200 $∆ T$
$∆ T$ =11760/210=56 K

Temperature of water will be 56 K

Regards

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$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, the rise in its temperature is (specific heat of copper = $420 J / k g /^{\circ} C$ , specific heat of water = $4200 J / k g /^{\circ} C$ )

$50 g$ of copper is heated to increase its temperature by $10^{\circ} C$ . If the same quantity of heat is given to $10 g$ of water, what will be the rise in its temperature? Assume no state change.
Specific heat of copper $= 420 J k g^{- 1 \circ} C$
Specific heat of water $= 4200 J k g^{- 1 \circ} C$

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certain amount of heat is given to 100g of copper to increase its temperature by 21 deg c. if the same amount of heat is given to 50 g of water, then the rise in its temperature is (specific heat of copper = 400 j kg^-1 k ^-1and that for water is 4200 j kg^-1 k^-1)

certain amount of heat is given to
100g of copper to increase its temperature by 21 deg c. if the same amount of heat is given to 50 g of water, then the rise in its temperature is (specific heat of copper = 400 j kg^-1 k ^-1and that for water is 4200 j kg^-1 k^-1)