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Byju's Answer
Standard IX
Physics
Kinetic Energy
Certain force...
Question
Certain force acting on a
20
k
g
mass changes its velocity from
5
m
s
−
1
to
2
m
s
−
1
. Calculate the work done by the force.
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Solution
Given : Initial velocity
u
=
5
m
/
s
Final velocity
v
=
2
m
/
s
The work done is equal to the change in the kinetic energy of an object.
W
=
1
2
m
(
v
2
−
u
2
)
W
=
1
2
×
20
×
(
2
2
−
5
2
)
⟹
W
=
−
210
J
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