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Question

Certain force acting on a 20 kg mass changes its velocity from 5 ms1 to 2 ms1. Calculate the work done by the force.

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Solution

Given : Initial velocity u=5 m/s
Final velocity v=2 m/s

The work done is equal to the change in the kinetic energy of an object.
W=12m(v2u2)

W=12×20×(2252)

W=210 J

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