Certain substance trimerizes when dissolved in a solvent, A. The Van't Hoff factor for the solution is:

2

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1 / 3

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3

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0

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Solution

The correct option is A $1 / 3$
The association equilibrium is as shown.
$3 A ⇌ A_{3}$
The expression for the Van't Hoff factor in cas of association is,
$i = \frac{Actual number of particles}{Number of particles for no association}$
Substitute values in the above expression.
$i = \frac{1}{3}$

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One mole of a solute A is dissolved in a given volume of a solvent. If solute undergoes association, it's Van't Hoff factor i is expressed as:

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