Certain wire has resistance of 10 Ohm. If it is stretched by 1/10th of its length, then its resistance is nearly:
9 Ω
10 Ω
11 Ω
12 Ω
As R = ρLA and Volume = L x A = Constant
Final Resistance = 1.12R = 1.21R = 12.1 Ω
If a wire of resistance R=10ohm is stretched to double of its length, then new resistance will be ______.