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Question

cos4θsin4θcos2θsin2θ=

A
1
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B
2
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C
cos θ +sin θ
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D
cos θ sin θ
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Solution

The correct option is A 1

The value of cos4θsin4θcos2θsin2θ
=(cos2θ+sin2θ)(cos2θsin2θ)(cos2θsin2θ)
=cos2θ+sin2θ
=1 ...... (Since, sin2θ+cos2θ=1)

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