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B
cos(π8−α2)
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C
tan(α2−π8)
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D
cot(α2−π2)
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Solution
The correct option is Dtan(α2−π8) √2−sinα−cosαsinα−cosα=√2[1−1√2sinα−1√2cosα]√2[1√2sinα−1√2cosα]=1−[sin450sinα+cos450cosα]cos450sinα−sin450cosα=1−[cos(α−π4)]sin(π4−α)=2sin2(α−π/42)2sin(π8−α2)cos(π8−α2)=tan(α2−π8)