Question

CFSE(${\Delta }_0$) for metal ion in $d^7$ configuration in presence of strong ligand field is____.

• A. $-0.6{\Delta }_0$
• B. $-0.8{\Delta }_0$
• C. $-1.6{\Delta }_0$
• D. $-1.8{\Delta }_0$

Answer 1

Answer: (B)

$-0.8{\Delta }_0$

The energy of isotopic field can be calculated by using by the following equation,

$E_{isotopicfield}=7\times 0+2P$

Energy of ligand field.

$E_{ligandfield}=7\times 0+2P$

$E_{ligandfield}=(5\times \frac{-2}{5}{\Delta }_0)+(2\times \frac{3}{5}{\Delta }_0)+2P$

therefore crystal field splitting energy cn be calculated as.

$CFSE=E_{ligandfield}-E_{Isotopicfield}$

$CFSE=(\frac{-4}{5}{\Delta }_0-2P)-2P$

$CFSE=\frac{-4}{5}{\Delta }_0=-0.8{\Delta }_0$

Hence,
$-0.8{\Delta }_0$ is the answer.