${C H}_{2} = {C H}_{2} + {B r}_{2} N a C l - -- \to P r o d u c t s$ . Which of the following product is not formed in the above reaction?

B r {C H}_{2} {C H}_{2} B r

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C l {C H}_{2} {C H}_{2} C l

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B r {C H}_{2} {C H}_{2} C l

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All are formed

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Solution

The correct option is A $C l {C H}_{2} {C H}_{2} C l$
Solution:- (B) $C l - C H_{2} - C H_{2} - C l$
$C H_{2} = C H_{2} + {B r}_{2} N a C l - -- \to {C H_{2}}^{+} - C H_{2} - B r$
The $π$ -electrons will attack an electrophile forming the carbocation.
Now the carbocation will be attacked by a nucleophile.
Hence the product will be a mixture of $B r - C H_{2} - C H_{2} - B r$ and $B r - C H_{2} - C H_{2} - C l$ .

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