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Byju's Answer
Standard X
Chemistry
Polymerization
CH2=CH2g+H2gN...
Question
C
H
2
=
C
H
2
(
g
)
+
H
2
(
g
)
N
i
(
s
)
→
C
H
3
−
C
H
3
For this reaction calculate the ratio of
t
75
and
t
50
(half life).
A
1.5
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B
2
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C
2.5
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D
1.25
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Solution
The correct option is
B
2
C
H
2
=
C
H
+
H
2
N
i
−
→
C
H
3
−
C
H
3
It is a first order reaction.
t
1
=
2.303
K
l
o
g
[
A
o
A
t
]
Let
A
o
=
100
;
A
75
=
100
−
75
=
25
;
A
50
=
100
−
50
=
50
t
75
t
50
=
2.303
K
l
o
g
[
A
o
A
75
]
2.303
K
l
o
g
[
A
o
A
50
]
⇒
t
75
t
50
=
l
o
g
[
100
25
]
l
o
g
[
100
50
]
t
75
t
50
=
l
o
g
(
4
)
l
o
g
(
2
)
=
2
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0
Similar questions
Q.
For the first - order reaction
T
a
v
(average life),
T
50
, and
T
75
in the increasing order are :
Q.
C
H
3
−
C
H
2
−
B
r
+
N
a
O
H
K
1
→
C
H
3
−
C
H
2
−
O
H
+
N
a
B
r
→
reaction
(
1
)
C
H
3
−
C
H
3
|
C
|
C
H
3
−
C
H
2
−
B
r
+
N
a
O
H
K
2
→
(
C
H
3
)
3
C
−
C
H
2
−
O
H
+
N
a
B
r
→
reaction
(
2
)
K
1
and
K
2
are the rate constant for the given reactions. The correct relation is:
Q.
C
H
3
−
C
H
2
−
C
H
2
−
O
−
C
|
|
S
−
S
−
C
H
3
undergoes elimination on strong heating giving
C
H
3
−
C
H
=
C
H
2
,
C
H
3
S
H
and
C
O
S
. This reaction involves :
Q.
What will be the end product of this reaction ?
C
H
2
=
C
H
2
+
H
.
H
2
S
O
4
→
Q.
Identify the type of the following reaction of carbon compounds.
a. CH
3
-CH
2
-CH
2
-OH → CH
3
-CH
2
-COOH
b. CH
3
-CH
2
-CH
3
→ 3CO
2
+ 4H
2
O
c. CH
3
-CH = CH -CH
3
+ Br
2
→ CH
3
-CHBr - CHBr -CH
3
d. CH
3
-CH
3
+ Cl
2
→ CH
3
-CH
2
-Cl + HCl
e. CH
3
-CH
2
-CH
2
-CH
2
-OH → CH
3
-CH
2
-CH=CH
2
+ H
2
O
f. CH
3
-CH
2
-COOH + NaOH → CH
3
-CH
2
-COO - Na
+
+ H
2
O
g. CH
3
-COOH + CH
3
-OH → CH
3
-COO- CH
3
+ H
2
O
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