CH2-CH2-H2-CO XX-H2YX and Y is-are -

Name: NEET - Grade 11 - Chemistry - Hydrogen and the S-block - Session 02 - D03
Uploaded: 2022-07-04T10:36:42+05:30
Description: Hydroformylation of olefins: It yields aldehydes, which further nbsp;undergo reduction to give alcohols. CH=CH_2+H_2+CO CH_2CH_2CHO CH_2CH_2CHO+H_2CH_2CH_2CH_ ...

Hydroformylation of olefins: It yields aldehydes, which further nbsp;undergo reduction to give alcohols. CH=CH_2+H_2+CO CH_2CH_2CHO CH_2CH_2CHO+H_2CH_2CH_2CH_ ...

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Byju's Answer

Standard XII

Chemistry

Other Reductions

CH2=CH2+H2+CO...

Question

$C H_{2} = C H_{2} + H_{2} + C O Catalyst - ---- \to X$

$X + H_{2} Catalyst - ---- \to Y$

X and Y is/are :

X and Y both are C H_{3} - C H_{3}

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X : C H_{2} C H_{2} C H O a n d Y : C H_{2} C H_{2} C H_{2} O H

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X : C H_{2} C H_{2} C H_{2} O H a n d Y : C H_{2} C H_{2} C H O

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X : C H_{2} C H_{2} O H a n d Y : C H_{2} C H O

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Solution

The correct option is B $X : C H_{2} C H_{2} C H O a n d Y : C H_{2} C H_{2} C H_{2} O H$
Hydroformylation of olefins:
It yields aldehydes, which further undergo reduction to give alcohols.
$C H = C H_{2} + H_{2} + C O Catalyst - ---- \to C H_{2} C H_{2} C H O$
$C H_{2} C H_{2} C H O + H_{2} Catalyst - ---- \to C H_{2} C H_{2} C H_{2} O H$

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Similar questions

The reaction of

H_{2}

is given below

H_{2}

+ CO + R—CH =

C H_{2}

\to

R — C H_{2}

—

C H_{2} — C H O

is specifically called as

Q. The reaction of

H_{2}

is given below

H_{2} + C O + R - C H = C H_{2} \to R - C H_{2} - C H_{2} - C H O

is specifically called as

Q. Explain the mechanism of the following reaction:

C H_{3} - C H_{2} - O H H^{+} - - \to 443 K C H_{2} = C H_{2} + H_{2}^{-} O

Q. Complete table.

Chemical reaction	Product	$I U P A C$ name of the product
$C H_{2} = C H_{2} + C l_{2}$	........	........
$C H_{2} = C H_{2} + H C l$	..........	.........
$C H_{3} - C h = C H_{2} + H_{2}$	..........	..........
$C H_{3} - C H = C H - C H_{3} + H B r$	...........	........

C H_{3} - C H_{2} - C H = C H_{2} + H B r R O O R (p e r o x i d e) - --------- \to (X) M a j o r + (Y) M i n o r

X and Y respectively are:

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Other Reductions

Standard XII Chemistry

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CH2=CH2+H2+COCatalyst−−−−−→X X+H2Catalyst−−−−−→Y X and Y is/are :

The correct option is B X:CH2CH2CHO and Y:CH2CH2CH2OHHydroformylation of olefins: It yields aldehydes, which further undergo reduction to give alcohols. CH=CH2+H2+COCatalyst−−−−−→CH2CH2CHO CH2CH2CHO+H2Catalyst−−−−−→CH2CH2CH2OH

$C H_{2} = C H_{2} + H_{2} + C O Catalyst - ---- \to X$

$X + H_{2} Catalyst - ---- \to Y$

X and Y is/are :