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Question

CH2=CH2+HBrA alc. KOH−−−−− B

B is :

A
Carboxylic acid
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B
Aldehyde
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C
Alcohol
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D
Alkene
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Solution

The correct option is D Alkene
First reaction is as follows:
CH2=CH2+HBrCH2BrCH3

In presence of alc. KOH, following reaction takes place:

CH3CH2Br+KOHCH2=CH2+KBr

In this process, alc. KOH is used for dehydrohalogenation.

Option D is correct.

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