CH 2- CH 2 PhCO 3 H - A H 3 O - B PI 3- -2 eq CStructure of C is

The correct option is B CH_2 =CH_2CH_2 =CH_2 O ∖CH_2 /CH_2OH|CH_2 OH|CH_2 nbsp;I|CH_2 I|CH_2 CH_2 = CH_2 Vicinal diodide undergoes nbsp; eliminat ...

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Alcohols as Nucleophiles and Electrophiles

CH 2= CH 2 Ph...

Question

$C H_{2} = C H_{2} P h C O_{3} H - ---- \to A H_{3} O^{\oplus} - -- \to B P I_{3}, △ - --- \to (2 e q) C$
Structure of C is

C | O H H_{2} - C | I H_{2}

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C H_{2} = C H_{2}

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C H_{2} ∖ - C / H_{2} O

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C | I H_{2} - C | I H_{2}

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Solution

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C H_{2} = C H_{2} P h C O_{3} H - ---- \to A H_{3} O^{\oplus} - -- \to B P I_{3}, Δ - --- \to (2 e q v .) C

C H_{3} - C H_{2} - C O O H C l_{2} - -- \to R e d P A N a C N - --- \to H_{3} O B △ - \to C

C

C H_{3} B r K C N \to A H_{3} O^{+} \to B L i A l H_{4} \to C

In the following sequence of reactions $C H_{3} - B r K C N \to A H_{3} O^{+} \to B L i A I H_{4} - ---- \to e t h e r C,$ the end product (C) is:

C_{2} H_{4} + C L_{2} \to \dots \dots

C_{2} H_{5} B r + K O H (a l c .) Δ - \to \dots \dots

H_{2} C = C H_{2} + 2 [O] a l k . K M n O_{4} - ------ \to \dots \dots

H_{2} C = C H_{2} + H B r \to \dots \dots

H_{2} C = C H_{2} + O_{3} \to \dots \dots

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