$C H_{2} = C H - C \equiv C H$

The hybrid state of C-atoms which are attached to a single bond with each other in the above structure are:

s p^{2}, s p

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s p^{3}, s p

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s p^{2}, s p^{2}

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s p^{2}, s p^{3}

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Solution

The correct option is A $s p^{2}, s p$
The hybrid state of the carbon atom attached to the double bond is $s p^{2}$ as the hybrid state of a carbon atom attached to the triple bond is $s p$ .

Hence, option $A$ is the correct answer.

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Similar questions

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

The hybridizations of the carbons numbered 1, 3 and 5 in the given hydrocarbon are respectively:

Q. In the hydrocarbon

C (1) H_{2} = C (2) H - C (3) \equiv C H

, the state of hybridisation of carbons 1, 2 and 3 respectively are:

A straight chain hydrocarbon has the molecular formula C8H10. The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be

Q. In the hydrocarbon

C (1) H_{2} = C (2) H - C (3) \equiv C H

, the state of hybridisation of carbons 1, 2 and 3 respectively are:

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

The hybridizations of the carbons numbered 1, 3 and 5 in the given hydrocarbon sequentially are:

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CH2=CH−C≡CHThe hybrid state of C-atoms which are attached to a single bond with each other in the above structure are:

The correct option is A sp2,spThe hybrid state of the carbon atom attached to the double bond is sp2 as the hybrid state of a carbon atom attached to the triple bond is sp.Hence, option A is the correct answer.

$C H_{2} = C H - C \equiv C H$

The hybrid state of C-atoms which are attached to a single bond with each other in the above structure are:

The correct option is A $s p^{2}, s p$
The hybrid state of the carbon atom attached to the double bond is $s p^{2}$ as the hybrid state of a carbon atom attached to the triple bond is $s p$ .

Hence, option $A$ is the correct answer.