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Question

CH2=CH−CH3i. Hg(OAc)2, THF−−−−−−−−−−−→ii. NaBH4P

CH2=CH−CH3i. B2H6, THF−−−−−−−−−→ii. H2O2, OH−Q

Predict the correct statement with respect to P and Q.

A
Both will yield iodoform on treatment with I2 and KOH
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B
Both undergo esterification at the same rate
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C
Both can be distinguished by victor meyer's test
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D
Pyridinium chlorochromate (PCC) oxidise P to aldehyde and Q to a ketone
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Solution

The correct option is C Both can be distinguished by victor meyer's test
CH2=CHCH3i. Hg(OAc)2, THF−−−−−−−−−−ii. NaBH4CH3CH(OH)CH3

CH2=CHCH3i. B2H6, THF−−−−−−−−ii. H2O2, OH(OH)CH2CH2CH3

P is secondary alcohol and Q is primary alcohol. Hence they can be distinguished by Victor meyer's test.

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