wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

CH2=CH−CH3i. Hg(OAc)2, THF−−−−−−−−−−−→ii. NaBH4P

CH2=CH−CH3i. B2H6, THF−−−−−−−−−→ii. H2O2, OH−Q

Predict the correct statement with respect to P and Q.

A
Both will yield iodoform on treatment with I2 and KOH
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Both undergo esterification at the same rate
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Both can be distinguished by victor meyer's test
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Pyridinium chlorochromate (PCC) oxidise P to aldehyde and Q to a ketone
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C Both can be distinguished by victor meyer's test
CH2=CHCH3i. Hg(OAc)2, THF−−−−−−−−−−ii. NaBH4CH3CH(OH)CH3

CH2=CHCH3i. B2H6, THF−−−−−−−−ii. H2O2, OH(OH)CH2CH2CH3

P is secondary alcohol and Q is primary alcohol. Hence they can be distinguished by Victor meyer's test.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Chemical Properties of Alcohols 1
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon