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Acidity of Carboxylic Acids

CH32C = CHCOC...

Question

$(C H_{3})_{2} C = C H C O C H_{3}$ can be oxidised to $(C H_{3})_{2} = C H C O O H$ by:

chromic acid

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N a O I

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C u

300^{\circ} C

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K M n O_{4}

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Solution

The correct option is A chromic acid
${(C H_{3})}_{2} C = C H C O C H_{3} C h r o m i c a c i d - ------- \to {(C H_{3})}_{2} = C H C O O H$
$H_{2} C r O_{4}$ strong oxidizing agent oxidizes carbonyl carbons to carboxylic acids, irrespective of carbon chain.

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Similar questions

Q. The products obtained when 2-methylpropene is oxidised with hot conc. acidic

K M n O_{4}

are .

Q. The products obtained when 2-Methylpropene is oxidised with hot conc. acidic

K M n O_{4}

are

[C H_{3}]_{2} C = C H C O C H_{3}

can be oxidized to

[C H_{3}]_{2} C = C H C O O H

by?

Which of the following reagents can be used to oxidise primary alcohols to aldehydes?
(a) $C r O_{3}$ in anhydrous medium
(b) $K M n O_{4}$ in acidic medium
(c) Pyridinium chlorochromate
(d) Heat in the presence of Cu at 573K

Q. The mixture of

C u S

(molar weight =

M_{1}

) and

C u_{2} S

(molecular weight =

M_{2}

) is oxidised by

K M n O_{4}

(molecular weight =

M_{4}

) in acidic medium, the product obtained are

C u^{2 +}

and

S O_{2 +}

. The equivalent weights of

C u S, C u_{2} S

and

K M n O_{4}

respectively, are :

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(CH3)2C=CHCOCH3 can be oxidised to (CH3)2=CHCOOH by:

The correct option is A chromic acid(CH3)2C=CHCOCH3Chromic acid−−−−−−−−→(CH3)2=CHCOOHH2CrO4 strong oxidizing agent oxidizes carbonyl carbons to carboxylic acids, irrespective of carbon chain.

$(C H_{3})_{2} C = C H C O C H_{3}$ can be oxidised to $(C H_{3})_{2} = C H C O O H$ by:

The correct option is A chromic acid
${(C H_{3})}_{2} C = C H C O C H_{3} C h r o m i c a c i d - ------- \to {(C H_{3})}_{2} = C H C O O H$
$H_{2} C r O_{4}$ strong oxidizing agent oxidizes carbonyl carbons to carboxylic acids, irrespective of carbon chain.