Question

$(C{H}_3{)}_{2}CO$
Which one is correct?

• A. $\begin{array}{ccccc}& & O& & \\ & & \parallel & & \\ C{H}_3& -& C& -& C{H}_3\\ \uparrow & & \uparrow & & \uparrow \\ s{p}^3& & s{p}^2& & s{p}^3\end{array}$
• B. $\begin{array}{ccccc}& & O& & \\ & & \parallel & & \\ C{H}_3& -& C& =& C{H}_3\\ \uparrow & & \uparrow & & \uparrow \\ s{p}^3& & s{p}^3& & s{p}^3\end{array}$
• C. $\begin{array}{ccccc}& & O& & \\ & & \parallel & & \\ C{H}_3& -& C& =& C{H}_3\\ \uparrow & & \uparrow & & \uparrow \\ s{p}^2& & s{p}^2& & s{p}^3\end{array}$
• D. $\begin{array}{ccccc}& & O& & \\ & & \parallel & & \\ C{H}_3& -& C& =& C{H}_3\\ \uparrow & & \uparrow & & \uparrow \\ s{p}^3& & s{p}^2& & s{p}^2\end{array}$

Answer 1

The correct option is A $\begin{array}{ccccc}& & O& & \\ & & \parallel & & \\ C{H}_3& -& C& -& C{H}_3\\ \uparrow & & \uparrow & & \uparrow \\ s{p}^3& & s{p}^2& & s{p}^3\end{array}$

In, $C{H}_2=C=O$ , carbon atom has only 4 electrons to share. So, it will form 4 bonds. Hence, only first structure is valid.