$(C H_{3})_{3} C - O H$ on treatmant with $N a C l$ in aqueous medium gives:

no reaction

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(C H_{3})_{3} C^{-} N a^{+}

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(C H_{3})_{3} C^{-} C;^{-}

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iso-butylene.

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Solution

The correct option is B no reaction
Alcohols doesn't react with Non-Acidic $N a C l$ , $N a B r$ . So , there is no reaction between ${(C H_{3})}_{3} C - O H$ and $N a C l$

Option A is correct

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