$(C H_{3})_{3}$ COH is less acid than $(C H_{3})_{3}$ SiOH. Why ?
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Solution

The correct option is A 0
Si has vacant d orbitals which are capable of accommodating electron pair form existing oxygen atom forming d-p back bonding.Deficiency of electrons on O atom causes bond pair of O-H to stay closer to O.This causes tendency of H atom to go out as cation increases.

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Similar questions

{(C H_{3})}_{3} C^{\oplus}

C H_{3} \oplus C H_{2}

\oplus C H_{3}

Which of the following carbocation is most stable?

(a) (b) (c)

(d)

(C H_{3})_{3} + N - O^{-} (C H_{3})_{3} + P - O^{-}

(C H_{3})_{3}

(S i H_{3})_{3} N

P H_{3} + \oplus N H_{4} ⟶ \oplus P H_{4} + N H_{3}

N H_{3} + P {\oplus H}_{4} ⟶ N {\oplus H}_{4} + P H_{3}

(C H_{3})_{3} P + \oplus N H_{4} ⟶ (C H_{3})_{3} \oplus P H + N H_{3}

(C H_{3})_{3} N + P H_{4}^{\oplus} ⟶ (C H_{3})_{3} \oplus N H + P H_{3}

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