$(C H_{3})_{3} C H K M n O_{4} - ---- \to A; C H_{3} (C H_{2})_{2} C H_{3} H C l - -- \to A l C l_{3} B; C H_{3} (C H_{2})_{4} C H_{3} C r_{2} O_{3}, 773 K - ------ \to 10 - 20 a t m C;$

Correct statements are

A. 'A' remains same B. 'B' contains a $3^{0}$ carbon

C. 'C' follows Huckel's rule D. Both B and C are aromatic

A, B, C only

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A, B, C ,D

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A, C, D only

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B, C only

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Solution

The correct option is A
A, B, C only

A does not undergo any change. There is no strong reason to support $K M n O_{4}$ attacks a tertiary alkane to give an alcohol

B forms a tertiary alkane through isomerisation

C forms a benzene ring through aromatization reaction

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Similar questions

$(C H_{3})_{3} C H K M n O_{4} - ---- \to A; C H_{3} (C H_{2})_{2} C H_{3} H C l - -- \to A l C l_{3} B; C H_{3} (C H_{2})_{4} C H_{3} C r_{2} O_{3}, 773 K - ------ \to 10 - 20 a t m C;$

Correct statements are

A. 'A' is tertiary alcohol B. 'B' contains a $3^{\circ}$ carbon

C. 'C' follows Huckel's rule D. both B and C are aromatic

Q. According to Huckel's rule, a compound is said to be aromatic, if it contains:

$3 C H C H C u, 500^{\circ} C - ----- \to A; A + 3 H_{2} N i - \to B$ Identify correct statement

Q. Consider the following two statements :
(A) Line spectra contain information about atoms.
(B) Band spectra contain information about molecules.
(a) Both A and B are wrong
(b) A is correct but B is wrong
(c) B is correct but A is wrong
(d) Both A and B are correct

Length and breadth of a rectangular sheet of a paper are $20 c m$ and $10 c m$ , respectively. A rectangular piece is cut from the sheet as shown in the given figure. Which of the following statements is correct for the remaining sheet?

(a) Perimeter remains the same but area changes

(b) Area remains the same but perimeter changes

(d) Both area and perimeter remain the same

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(CH3)3CHKMnO4−−−−−→A;CH3(CH2)2CH3HCl−−−→AlCl3B;CH3(CH2)4CH3Cr2O3,773K−−−−−−−→10−20 atmC; Correct statements are A. 'A' remains same B. 'B' contains a 30 carbon C. 'C' follows Huckel's rule D. Both B and C are aromatic

The correct option is A A, B, C only A does not undergo any change. There is no strong reason to support KMnO4 attacks a tertiary alkane to give an alcohol B forms a tertiary alkane through isomerisation C forms a benzene ring through aromatization reaction

The correct option is A
A, B, C only

A does not undergo any change. There is no strong reason to support $K M n O_{4}$ attacks a tertiary alkane to give an alcohol

B forms a tertiary alkane through isomerisation

C forms a benzene ring through aromatization reaction