$(C H_{3})_{3} P = O$ exists but $(C H_{3})_{3} N = O$ does not. Give reasons.

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Solution

Due to absence of d-orbitals in valence shell,cannot form $d π - p π$ multiple bonds ,so nitrogen cannot form $(C H_{3})_{3} N = 0$ .while in phosphorous, it has d-orbitals in its valance shell so, it can from $d π - p π$ multiple bonds ,so $(C H_{3})_{3} P = 0$ exists

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