Question

$(C{H}_3{)}_{3}P=O$ exists but $(C{H}_3{)}_{3}N=O$ does not. Give reasons.

Answer 1

Due to absence of d-orbitals in valence shell,cannot form $d\pi -p\pi$ multiple bonds ,so nitrogen cannot form $(C{H}_3{)}_{3}N=0$.while in phosphorous, it has d-orbitals in its valance shell so, it can from $d\pi -p\pi$ multiple bonds ,so $(C{H}_3{)}_{3}P=0$ exists