Question

${CH}_3-Br+{Nu}^{\ominus }⟶{CH}_3-Nu+Br$
The decreasing order of the rate of the above reaction with nucleophile $\left({Nu}^{\ominus }\right)\left(A\right)$ to $\left(D\right)$ is:
$[{Nu}^{\ominus }\Rightarrow (A\left)Ph{O}^{\ominus }\right(B\left)AC{O}^{\ominus }\right(C\left)\stackrel{\ominus }{O}H\right(D){CH}_3{O}^{\ominus }$]

• A. $\left(D\right)>\left(C\right)>\left(A\right)>\left(B\right)$
• B. $\left(D\right)>\left(C\right)>\left(B\right)>\left(A\right)$
• C. $\left(C\right)>\left(D\right)>\left(A\right)>\left(B\right)$
• D. $\left(B\right)>\left(D\right)>\left(C\right)>\left(A\right)$

Answer 1

The correct option is C $\left(C\right)>\left(D\right)>\left(A\right)>\left(B\right)$

Acidic character:
$ACOH>PhOH>MeOH>H_{2}O$
$p{K}_a$ value: $4.75,\mathrm{9.9.15.5},15.74$ respectively.
Basic and nucleophilic centre.
Nucleophilic order:
$Ac{O}^{\ominus }<Ph{O}^{\ominus }<Me{O}^{\ominus }<\stackrel{\ominus }{O}H$
$\left(B\right)<\left(A\right)<\left(D\right)<\left(C\right)$