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Question
CH3−C≡CHHgSO4→dil.H2SO4(A)
CH3−C≡CH(1)BH3⋅THF→(2)H2O2/HO−(B).
Product (A) and (B) is differentiated by.
CH3−C≡CH(1)BH3⋅THF→(2)H2O2/HO−(B).
Product (A) and (B) is differentiated by.
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Solution
The correct option is D NaOI
OH OCH3−C≡CHHg2+/H+−−−−−−→H2OCH3−|C=CH2⇌CH3↓−||C−CH3 A ketone (positive iodoform test with NaOI)CH3−C≡CH(1)BH3THF−−−−−−−−→(2)H2O/OH−CH3−CH=CH2−OH⇌CH3−CH2−CHO Aldehyde (negative iodoform because ketone group is absent)
OH O
CH3−C≡CHHg2+/H+−−−−−−→H2OCH3−|C=CH2⇌CH3↓−||C−CH3
A ketone (positive iodoform test with NaOI)
CH3−C≡CH(1)BH3THF−−−−−−−−→(2)H2O/OH−CH3−CH=CH2−OH⇌CH3−CH2−CHO
Aldehyde (negative iodoform because ketone group is absent)
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