$C H_{3} - C H_{2} - C H_{2} - B r A l c . K O H ⟶$ Final product is

Propanol

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Propene

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Cyclopropane

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Propane-l, 2-diol

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Solution

The correct option is B Propene
When primary haloalkane containing $β$ - hydrogen atom is heated with alc. KOH solution, then alkene is formed.
In this reaction, hydrogen is eliminated from $β - c a r b o n$ and the halogen is lost from $α - c a r b o n$ atom. As a result, an alkene is formed as a product.
Hence, option (a) is correct.

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