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Byju's Answer
Standard XII
Chemistry
Nucleophilic Substitution in Alkyl Halides
CH 3 CH 2 CH ...
Question
C
H
3
C
H
2
C
H
2
B
r
N
H
3
−
−−−
→
e
x
c
e
s
s
C
H
3
C
H
2
C
H
2
N
H
2
If given product is right then, enter 1 else 0.
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Solution
When n propyl bromide is treated with excess of ammonia, n propyl amine is obtained as the product.
C
H
3
C
H
2
C
H
2
B
r
N
H
3
−
−−−
→
e
x
c
e
s
s
C
H
3
C
H
2
C
H
2
N
H
2
In this reaction, bromide is replaced with amino group.
This is an example of
S
2
N
mechanism.
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Similar questions
Q.
C
H
3
C
H
=
C
H
2
+
B
.
r
→
C
H
3
.
C
H
2
B
r
Q.
In the given example B,C and B,D are
:
(a)
C
H
3
−
C
H
2
−
C
H
2
−
C
H
2
N
H
2
Butanamine
(
1
o
)
(b)
C
H
3
−
C
H
2
−
N
H
2
|
C
H
−
C
H
3
Butan-2-amine
(
1
o
)
(c)
C
H
3
−
C
H
3
|
C
H
−
C
H
2
−
N
H
2
2-Methylpropanamine
(
1
o
)
(d)
C
H
3
−
C
H
3
|
C
|
−
C
H
3
N
H
2
2-methylpropan-2-amine
(
1
o
)
(e)
C
H
3
−
C
H
2
−
C
H
2
−
N
H
−
C
H
3
N-methylpropanamine
(
2
o
)
Q.
End product in this reaction is
C
H
C
H
+
H
B
r
→
X
K
O
H
→
Q.
In the given compound A,C and A,D are exbhits which of the following isomerism :
(a)
C
H
3
−
C
H
2
−
C
H
2
−
C
H
2
N
H
2
Butanamine
(
1
o
)
(b)
C
H
3
−
C
H
2
−
N
H
2
|
C
H
−
C
H
3
Butan-2-amine
(
1
o
)
(c)
C
H
3
−
C
H
3
|
C
H
−
C
H
2
−
N
H
2
2-Methylpropanamine
(
1
o
)
(d)
C
H
3
−
C
H
3
|
C
|
−
C
H
3
N
H
2
2-methylpropan-2-amine
(
1
o
)
(e)
C
H
3
−
C
H
2
−
C
H
2
−
N
H
−
C
H
3
N-methylpropanamine
(
2
o
)
Q.
Arrange the following compounds in increasing order of their boiling points.
I.
C
H
3
C
H
2
C
H
2
B
r
II.
C
H
3
C
H
2
C
H
2
C
H
2
B
r
III.
(
C
H
3
)
2
C
H
C
H
2
B
r
IV.
(
C
H
3
)
3
C
B
r
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