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Question
CH3−CH2−CH3(g)→P+CH4(g)
Identify P in the given reaction.
Identify P in the given reaction.
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Solution
The correct option is C Ethene
The reaction in which hydrocarbons with high molecular masses, on heating in the absence of air, form hydrocarbons with lower molecular masses is known as a thermal cracking reaction.
∙ However, the total number of carbon and hydrogen atoms present in the hydrocarbon with higher molecular mass will be equal to the number of carbon and hydrogen atoms of product present in total.
∙ In the given reaction propane is undergoing thermal cracking to form methane and 'P' will be a compound having two carbon atoms and four hydrogen atoms. Therefore, 'P' is ethene. The chemical reaction for the same is given below: CH3−CH2−CH3(g)→CH2=CH2(g)+CH4(g)
The reaction in which hydrocarbons with high molecular masses, on heating in the absence of air, form hydrocarbons with lower molecular masses is known as a thermal cracking reaction.
∙ However, the total number of carbon and hydrogen atoms present in the hydrocarbon with higher molecular mass will be equal to the number of carbon and hydrogen atoms of product present in total.
∙ In the given reaction propane is undergoing thermal cracking to form methane and 'P' will be a compound having two carbon atoms and four hydrogen atoms. Therefore, 'P' is ethene. The chemical reaction for the same is given below:
CH3−CH2−CH3(g)→CH2=CH2(g)+CH4(g)
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