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Question

CH3CH2CH=CH2+HBrROOR(peroxide)−−−−−−−−−(X)Major+(Y)Minor
X and Y respectively are:

A
BrCH2CH2CH=CH2 and C2H5CH(Br)CH3
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B
C2H5CH2CH2Br and BrCH2CH2CH=CH2
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C
C2H5CH2CH2Br and C2H5CH(Br)CH3
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D
C2H5CH(Br)CH3 and C2H5CH2CH2Br
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Solution

The correct option is C C2H5CH2CH2Br and C2H5CH(Br)CH3
CH3CH2CH=CH2+HBrROOR/peroxideCH3CH2CH2CH2Br(major) +
CH3CH2CH(Br)CH3(Minor)

Anti-Markonikoff's rule: The negative part of the reagent will be added on to the carbon which is having more number of carbon atoms will be the major product.

Hence option C is correct.

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