CH3−CH2−CH=CH2+HBrROOR(peroxide)−−−−−−−−−−→(X)Major+(Y)Minor X and Y respectively are:
A
BrCH2−CH2−CH=CH2 and C2H5−CH(Br)−CH3
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B
C2H5−CH2−CH2Br and Br−CH2−CH2−CH=CH2
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C
C2H5−CH2−CH2Br and C2H5−CH(Br)−CH3
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D
C2H5CH(Br)−CH3 and C2H5−CH2−CH2Br
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Solution
The correct option is CC2H5−CH2−CH2Br and C2H5−CH(Br)−CH3 CH3−CH2−CH=CH2+HBrROOR/peroxide⟶CH3−CH2−CH2−CH2Br(major) +
CH3−CH2−CH(Br)−CH3(Minor)
Anti-Markonikoff's rule: The negative part of the reagent will be added on to the carbon which is having more number of carbon atoms will be the major product.